Showing posts with label Replace. Show all posts
Showing posts with label Replace. Show all posts

27 October 2018

Wish List: Replace From

    With SQL Server 2017 Microsoft introduced the Trim function, which not only replaces the combined use of LTrim and RTrim functions, but also replaces other specified characters from the start or end of a string (see my previous post):

-- Trim special characters 
SELECT Trim ('# ' FROM '# 843984 #') Example1
, Trim ('[]' FROM '[843984]') Example2
Output:
Example1   Example2
---------- --------
843984     843984

  Similarly, I wish I had a function that replaces special characters from a whole string (not only the trails), for example:

-- Replace special characters 
SELECT Replace ('# ' FROM '# 84#3984 #', '') Example1
, Replace ('[]' FROM '[84][39][84]', '') Example2

   Unfortunately, as far I know, there is no such simple function. Therefore, in order to replace the “]”, “[“ and “#” special characters from a string one is forced either to write verbose expressions like in the first example or to include the logic into a user-defined function like in the second:

-- a chain of replacements 
SELECT Replace(Replace(Replace('[#84][#39][#84]', '[' , ''), ']', ''), '#', '') Example1

-- encapsulated replacements
CREATE FUNCTION [dbo].[ReplaceSpecialChars](
  @string nvarchar(max)
, @replacer as nvarchar(1) 
) RETURNS nvarchar(max)
-- replaces the special characters from a string with a given replacer
AS
BEGIN   
  IF CharIndex('#', @string) > 0  
     SET @string = replace(@string, '#', @replacer) 
        
  IF CharIndex('[', @string) > 0  
     SET @string = replace(@string, '[', @replacer) 
    
  IF CharIndex(']', @string) > 0  
     SET @string = replace(@string, ']', @replacer) 
                                
  RETURN Trim(@string)
END

-- testing the function 
SELECT [dbo].[ReplaceSpecialChars]('[#84][#39][#84]', '') Example2

  In data cleaning the list of characters to replace can get considerable big (somewhere between 10 and 30 characters). In addition, one can deal with different scenarios in which the strings to be replaced differ and thus one is forced to write multiple such functions.

   To the list of special characters often needs to be considered also language specific characters like ß, ü, ä, ö that are replaced with ss, ue, ae, respectively oe (see also the post). 

  Personally, I would find such a replace function more than useful. What about you? 

Happy coding!

11 March 2011

SQL Reloaded: Pulling the Strings of SQL Server VIII (Insertions, Deletions and Replacements)

Until now, the operations with strings resumed to concatenation and its reverse operation(s) - extracting a substring or splitting a string into substrings. It was just the warm up! There are several other important operations that involve the internal manipulation of strings – insertion, deletion and replacement of a substring in a given string, operations performed using the Replace and Stuff functions.

Replace function, as its name denotes, replaces all occurrences of a specified string value with another. Several scenarios in which the function is quite useful: the replacement of delimiters, special characters, correcting misspelled words or any other chunks of text. Here are some basic simple examples, following to consider the before mentioned applications in other posts:

-- examples with replace 
DECLARE @str varchar(30) 
SET @str = 'this is a test string' 
SELECT replace(@str, ' ', ',') Example1 
, replace(@str, ' ', ' ') Example2 
, replace(@str, ' ', '') Example3 
, replace(@str, 'is', 'as') Example4  
Output:
Example1 Example2 Example3 Example4
this,is,a,test,string this is a test string thisisateststring thas as a test string

When there are good chances that the searched string won’t appear in the “searched” string, and especially when additional logic is depending on the replacement, logic that could be included in the same expression with the replacement, then maybe it makes sense to check first if the searched character is present:

-- replacement with check 
DECLARE @str varchar(30) 
DECLARE @search varchar(30) 
DECLARE @replacememt varchar(30) 
SET @str = 'this is a test string' 
SET @search = 'this string' 
SET @replacememt = 'other string' 
SELECT CASE            
    WHEN CharIndex(@search, @str)>0 THEN Replace(@str, @search, @replacememt)             
    ELSE @str        
END result 

Unfortunately the function doesn’t have the flexibility of the homonym functions provided by the languages from the family of VB (VBScript, VB.NET), which allow to do the replacement starting with a given position, and/or for a given number of occurrences. This type of behavior could be obtained with a simple trick – splitting the string into two other strings, performing the replacement on the second string, and then concatenating the first string and the result of the replacement:

-- replacement starting with a given position 
DECLARE @str varchar(30) 
DECLARE @search varchar(30) 
DECLARE @replacememt varchar(30) 
DECLARE @start int 
SET @str = 'this is a test string' 
SET @search = 's' 
SET @replacememt = 'x' 
SET @start = 7 
SELECT Left(@str, @start-1) FirstPart 
, RIGHT(@str, Len(@str)-@start+1) SecondPart 
, CASE        
    WHEN @start <= LEN(@str) THEN Left(@str, @start-1) + Replace(RIGHT(@str, Len(@str)-@start+1), @search, @replacememt)        
     ELSE @str  
END Replacement 
Output:
FirstPart SecondPart Replacement
this i s a test string this ix a text xtring

The logic can be encapsulated in a function together with additional validation logic.

Stuff function inserts a string into another string starting with a given position and deleting a specified number of characters. Even if seldom used, the function it’s quite powerful allowing to insert a string in another, to remove a part of a string or more general, to replace a single occurrence of a string with another string, as can be seen from the below examples:
 
-- Stuff-based examples DECLARE @str varchar(30) 
SET @str = 'this is a test string' 
SELECT STUFF(@str, 6, 2, 'was ') Example1 
, STUFF(@str, 1, 0, 'and ') Example2 
, STUFF(@str, 1, 0, 'that') Example3 
, STUFF(@str, LEN(@str) + 1, 0, '!') Example4 
Output:
Example1 Example2 Example3 Example4
this was a test string and this is a test string thatthis is a test string NULL

If in the first example is done a replacement of a text from a fix position, in the next examples are attempted insert on a first, middle respectively end position. As can be seen, the last example doesn’t work as expected, this because the insert position can’t go over the length of the target string. Actually, if the insert needs to be done at the beginning, respectively the end of a string, a concatenation can be much easier to use. A such example is the padding of strings with leading or trailing characters, typically in order to arrive to a given length. SQL Server doesn’t provide such a function, however the function is quite easy to build.
 
-- left/right padding DECLARE @str varchar(30) 
DECLARE @length int  
DECLARE @padchar varchar(1) 
SET @str = '12345'  
SET @length = 10 
SET @padchar = '0' 
SELECT @str StringToPad  
, CASE  
     WHEN LEN(@str)<@length THEN Replicate(@padchar, @length-LEN(@str)) + @str       
     ELSE @str  
END LeftPadding  
, CASE  
     WHEN LEN(@str)<@length THEN @str + Replicate(@padchar, @length-LEN(@str))      
     ELSE @str  
END RightPadding 
 
Output:
StringToPad LeftPadding RightPadding
12345 0000012345 1234500000

Happy Coding!

14 November 2005

SQL Reloaded: Out of Space

Some time ago I found a post in which somebody was annoyed of writing code like this:

DECLARE @zipcode char(5)

SET @zipcode = '90'

SELECT CASE len(@zipcode)
 WHEN 1 THEN '0000' + @zipcode
 WHEN 2 THEN '000' + @zipcode
 WHEN 3 THEN '00' + @zipcode
 WHEN 4 THEN '0' + @zipcode
 WHEN 5 THEN @zipcode
END

I remembered I met the same situation, but instead of writing a line of code for each case, I prefered to write a simple function, which used the Space and Replace built-in functions to add first a number of spaces and then replace them with a defined character. Maybe somebody will argue about the performance of such a function, but I prefer in many cases the reusability against performance, when the difference is not that big. Additionally, this enhances code’s readability.    

So, here is the function:

CREATE FUNCTION dbo.FillBefore(
   @target varchar(50)
 , @length int
 , @filler char(1))
/*
   Purpose: enlarges a string to a predefiend length by puting in front of it the same character
   Parameters: @target varchar(50) - the string to be transformed
  , @length int - the length of output string
  , @filler char(1) - the character which will be used as filler 
   Notes: the function works if the length of @length is greater or equal with the one of the @target, otherwise will return a NULL
*/
RETURNS varchar(50)
AS
BEGIN
   RETURN Replace(Space(@length-len(IsNull(@target, ''))), ' ', @filler) 
       + IsNull(@target, '')
END

-- testing the function
SELECT dbo.FillBefore('1234', 5, '0')
SELECT dbo.FillBefore('1234', 10, ' ')
SELECT dbo.FillBefore(1234, 10, ' ')
SELECT dbo.FillBefore(Cast(1234 as varchar(10)), 10, '0')

Another scenario in which the Space function was useful was when I had to save the result of a query to a text file in fixed width format. It resumes to the same logic used in FillBefore function, except the spaces must be added at the end of the string. For this I just needed to modify the order of concatenation and create a new function:

CREATE FUNCTION dbo.FillAfter(
   @target varchar(50)
 , @length int
 , @filler char(1))
/*
   Purpose: enlarges a string to a predefiend length by adding at the end the same character
   Parameters: @target varchar(50) - the string to be transformed
  , @length int - the length of output string
  , @filler char(1) - the character which will be used as filler 
   Notes: the function works if the length of @length is greater or equal with the one of the @target, otherwise will return a NULL

*/
RETURNS varchar(50)
AS
BEGIN
   RETURN IsNull(@target, '') 
        + Replace(Space(@length-len(IsNull(@target,''))), ' ', @filler)
END

  -- testing the function 
  SELECT dbo.FillAfter('1234', 5, '0')
  SELECT dbo.FillAfter('1234', 10, ' ')
  SELECT dbo.FillAfter(1234, 10, '0')
  SELECT dbo.FillAfter(Cast(1234 as varchar(10)), 10, '0')
  SELECT dbo.FillAfter(NULL, 10, '0')

Notes:
1.    In SQL Server 2005, the output of a query can be saved using a DTS Package with fix format directly to a text file using ‘fixed width’ (the columns are defined by fix widths) or ‘ragged right’ (the columns are defined by fix widths, except the last one which is delimited by the new line character) format for the destination file.
2.    To document or not to document. I know that many times we don't have the time to document the database objects we created, but I found that a simple comment saved more time later, even if was about my or other developer's time.
3.    If is really needed to use the CASE function, is good do a analysis of the data and put as first evaluation the case with the highest probability to occur, as second evaluation the case with the second probability to occur, and so on. The reason for this is that each option is evaluated until the comparision operation evaluates to TRUE. For example, if the zip codes are made in most of the cases of 5 characters, then it makes sense to put it in the first WHEN position.
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