23 September 2007

💎SQL Reloaded: 6 out of 49 (Part 3: Basic Data Analysis)

The most basic information one can get is the number of drawings in which a number occurred, respectively which was its frequency:

-- number & frequency drawings by number
DECLARE @NumberDrawings int = 2000
SELECT Number 
, Cast(100.0*count(*)/@NumberDrawings as decimal(10,2)) Frequency 
, count(*) NumberDrawings 
FROM dbo.vLottoNumbers 
GROUP BY Number 
ORDER BY Number  

One of the interesting things to see in a data set of drawings is the distance between two drawings in which appears the same numbers. It doesn’t look too easy to compare two consecutive records within the same query; actually this can be done easy with the help of DENSE_RANK function (works only on SQL Server 2005+ and Oracle), which ranks the data within a partition, thus if two values are identical, they have the same ranking. Let’s see how DENSE_RANK function works: 

-- ranked drawings by number
SELECT Number 
, DrawingDate 
, DENSE_RANK() OVER (PARTITION BY Number ORDER BY DrawingDate) Ranking 
FROM dbo.vLottoNumbers   

The partition is created by Number, while the ranking is delimited by DrawingDate. Now all we have to do is to join two such queries by Number with two consecutive Rankings: 

--creating the view 
CREATE VIEW dbo.vLottoConsecutiveDrawings 
AS 
-- consecutive drawings by numbers
WITH DAT 
AS (
	SELECT Number     
	, DrawingDate     
	, DENSE_RANK() OVER (PARTITION BY Number ORDER BY DrawingDate) Ranking   
	FROM dbo.vLottoNumbers  
)
SELECT A.Number 
, A.DrawingDate 
, B.DrawingDate NextDrawingDate 
, IsNull(DateDiff(d, A.DrawingDate, B.DrawingDate), 0) DifferenceDays 
, IsNull(DateDiff(wk, A.DrawingDate, B.DrawingDate), 0) DifferenceWeeks 
FROM DAT A
     LEFT JOIN DAT B 
	   ON A.Number = B.Number 
	  AND A.Ranking = B.Ranking - 1 

The first interesting thing to find out is:     
  • What’s the average number of occurrences?     
  • What’s the minimum/maximum number of consecutive drawings in which the number hasn’t appeared?  
  • How many times a number appeared?      
The following query answers to these questions, by doing a simple grouping by Number over vLottoConsecutiveDrawings output:

-- minimum/maximum differences between drawings
SELECT Number 
, Min(NullIf(DifferenceWeeks, 0)) Minimum 
, Max(NullIf(DifferenceWeeks, 0)) Maximum 
, Avg(NullIf(DifferenceWeeks, 0)) Average 
, count(*) NumberDrawings 
FROM dbo.vLottoConsecutiveDrawings 
GROUP BY Number 
ORDER BY Number    

The output doesn’t give much information, but it’s a good start. The study interval can be broken down by using the DrawingDate in GROUP and/or WHERE clause: 

-- minimum/maximum differences between drawings by year
SELECT Year(DrawingDate) DrawingYear 
, Number 
, Min(NullIf(DifferenceWeeks, 0)) Minimum 
, Max(NullIf(DifferenceWeeks, 0)) Maximum 
, Avg(NullIf(DifferenceWeeks, 0)) Average 
, count(*) NumberDrawings 
FROM vLottoConsecutiveDrawings 
--WHERE Year(DrawingDate) IN (2000, 2001) 
GROUP BY Number 
, Year(DrawingDate) 
ORDER BY Number, DrawingYear

It would be also interesting to know how many numbers fall on a given row or column within the 7x7 matrix:

-- aggregating data by drawing & row
SELECT LN.DrawingDate 
, SUM(CASE WHEN LN.Number BETWEEN 1 AND 7 THEN 1 ELSE 0 END) Bucket1
, SUM(CASE WHEN LN.Number BETWEEN 8 AND 14 THEN 1 ELSE 0 END) Bucket2
, SUM(CASE WHEN LN.Number BETWEEN 15 AND 21 THEN 1 ELSE 0 END) Bucket3
, SUM(CASE WHEN LN.Number BETWEEN 22 AND 28 THEN 1 ELSE 0 END) Bucket4
, SUM(CASE WHEN LN.Number BETWEEN 29 AND 35 THEN 1 ELSE 0 END) Bucket5
, SUM(CASE WHEN LN.Number BETWEEN 36 AND 42 THEN 1 ELSE 0 END) Bucket6
, SUM(CASE WHEN LN.Number BETWEEN 43 AND 49 THEN 1 ELSE 0 END) Bucket7
FROM dbo.vLottoNumbers LN 
GROUP BY LN.DrawingDate 

-- aggregating data by drawing & column
SELECT LN.DrawingDate 
, SUM(CASE WHEN LN.Number %7 = 1 THEN 1 ELSE 0 END) Bucket1
, SUM(CASE WHEN LN.Number %7 = 2 THEN 1 ELSE 0 END) Bucket2
, SUM(CASE WHEN LN.Number %7 = 3 THEN 1 ELSE 0 END) Bucket3
, SUM(CASE WHEN LN.Number %7 = 4 THEN 1 ELSE 0 END) Bucket4
, SUM(CASE WHEN LN.Number %7 = 5 THEN 1 ELSE 0 END) Bucket5
, SUM(CASE WHEN LN.Number %7 = 6 THEN 1 ELSE 0 END) Bucket6
, SUM(CASE WHEN LN.Number %7 = 7 THEN 1 ELSE 0 END) Bucket7
FROM dbo.vLottoNumbers LN 
GROUP BY LN.DrawingDate 

The buckets can be aggregated as follows (observe the replacement of SUM with MAX):
 
-- consolidated drawings by 7 buckets (row)
 SELECT SUM(Bucket1) Bucket1
, SUM(Bucket2) Bucket2
, SUM(Bucket3) Bucket3
, SUM(Bucket4) Bucket4
, SUM(Bucket5) Bucket5
, SUM(Bucket6) Bucket6
, SUM(Bucket7) Bucket7
 FROM (
     -- aggregating data by drawing & row
	 SELECT LN.DrawingDate 
	, Max(CASE WHEN LN.Number BETWEEN 1 AND 7 THEN 1 ELSE 0 END) Bucket1
	, Max(CASE WHEN LN.Number BETWEEN 8 AND 14 THEN 1 ELSE 0 END) Bucket2
	, Max(CASE WHEN LN.Number BETWEEN 15 AND 21 THEN 1 ELSE 0 END) Bucket3
	, Max(CASE WHEN LN.Number BETWEEN 22 AND 28 THEN 1 ELSE 0 END) Bucket4
	, Max(CASE WHEN LN.Number BETWEEN 29 AND 35 THEN 1 ELSE 0 END) Bucket5
	, Max(CASE WHEN LN.Number BETWEEN 36 AND 42 THEN 1 ELSE 0 END) Bucket6
	, Max(CASE WHEN LN.Number BETWEEN 43 AND 49 THEN 1 ELSE 0 END) Bucket7
	 FROM dbo.vLottoNumbers LN 
	 GROUP BY LN.DrawingDate 
  ) DAT

Happy coding!

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